4x^2=41x-45

Solution for 4x^2=41x-45 equation:

4x^2=41x-45

We move all terms to the left:

4x^2-(41x-45)=0

We get rid of parentheses

4x^2-41x+45=0

a = 4; b = -41; c = +45;
Δ = b2-4ac
Δ = -412-4·4·45
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-31}{2*4}=\frac{10}{8}
=1+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+31}{2*4}=\frac{72}{8}
=9
$